Bash variable with double quotes. Bash: Escaping double quotes in $() command substitution.

Bash variable with double quotes However, I personally recommend disabling bash expansion in you shell by adding set +H or set +o histexpand to your . How to match double and single quotes at the same time with the sed command? 0. Backslashes preceding characters without a special meaning are left unmodified. Viewed 4k times 3 I have the following command, which I am trying to append to my ~/. Perhaps there's a more elegant solution, but this is what I was able to come up with. When you have "'$0'", only those outer quotes are syntactic (and control how the shell expands the value: The inner quotes are simply literal values, and don't change how $0 is treated. As commented by hex2mgl you are removing the newlines with tr. From section 2. So insert a single quote after the double quote, put your variable to evaluate, and re-insert a quote after your variable. nl=$'\n' svn ci -m"Added new file: ${oFileName}${nl}Orig loc: ${oFileFull}" "${oFileName}" so as to escape the single-quote, enter a double-quote and thereby insert the variable value. The double-quoting of patterns is different depending on where the double-quotes are placed. Improve this question. See When is double-quoting necessary? for more details about the cases when you can leave out the quotes. Single characters can be quoted with the backslash (\), multiple characters can be quoted with single quotes (') or double quotes ("). They are optional in contexts where a single raw string is expected by the parser. For example, compare bash and dash: $ bash script. Unless you mean for all this rigmarole to happen, just remember to always use double quotes around variable and command substitutions. Always wrap strings and scripts in single quotes unless you need to use double quotes (e. /program is a program that just prints out the parameters; $ . In your array version, double quotes escaped by a backslash become part of the arguments, which is not intended. 2. How to escape quotes in bash? 1. How to add a variable inside a double quoted string. Here's an example that touches on escaping in sed but also captures some other quoting issues in bash: From the image, you can see that I have directly escaped the double quotes that are enclosed within a single-quoted string without using any characters. Could you please tell me if both usage below are correct use of double-quotes? How to add backslash and double quote to a string in bash. When a string has neither variables nor whitespace, there is no reason (other than style) to use any quotes at all. Bash ls with double substitution. – Suhas. It works fairly well, but is causing some issues on the data import without the enclosing double quotes. like: ${list} (before appending) => ' As you can notice that the login_token value is embedded with double quotes when passed as a variable and this causes the failure. It does not work with double-quotes either, nor with $*. The empty double quotes is treated as an argument and so two spaces are printed out between a an b. Hot Network Questions Do I understand my home's main breaker box? For this reason, I have added the escaped double quotes in the variable: p="\"a a\",\"b\"". In fact, it's the user of that variable that needs to expand it within double quotes to avoid wrong splitting. Bash Single vs. How bash treats strings in double quotes is described in full detail in man bash: Enclosing characters in double quotes preserves the literal value of all characters within the quotes, with the exception of $, `, \, and, when history expansion is enabled, !. g. As @chepner points out, you're free to choose the method of quoting in this case: enclose the delimiter in single quotes or double quotes, or even simply arbitrarily escape one character in the delimiter with \: echo "creating new script file. RIP Tutorial. ; Access to the terminal (Ctrl+Alt+T). using sed with variables to replace quoted string in bash. Within single quotes, every special character except ' gets interpreted literally. 3 ${parameter:?word} expansion: `\}` difference between bash and zsh. I want to mosquitto_pub the I'm trying to write a bash script that takes a variable and populates it inside a somewhat complex string and I can't figure out how to get it to work. Modified 10 years, true but even if I pass it with commit directly from command line I would have to escape. Viewed 190 times 1 I have a few questions about variable assignment and command substitution: Why does \"<Enter> add a new line to the output $ v1="1\" 2" $ echo If you want to store in an array the list of files resulting from the expansion of a glob pattern stored in variable, in bash, that would be:. Words of the form $'string' are treated assuming in your string there is no variable, command or history expansion, and there is no How to use bash variable with double and single quotes. For example, running the following command will Variable substitutions should only be used inside double quotes. I want to put the variables, I got by read, in a file with cat << EOF >> file. Also, bash:variable with double quotes. I have the following what you have is a single-quoted string. Some expansion occurs within double quotes, while other characters are treated as literals. Viewed 1k times 3 . An unquoted, but escaped, single quote. In short, quote everything where you do not require the shell to perform word When the shell expands a variable on the command line, if the variable was in double-quotes it's not parsed; if it was not in quotes, spaces in it are parsed as argument I am trying to run a command in shell script which demands its argument to be passed in below format which includes double quotes with string. I am trying to run a command in shell script which demands its argument to be passed in below format which includes double quotes with string. case statements and assignments are the only places I intuitively accept that the variable is not subject to field splitting, but even in those cases I would double quote the expression. Don't use eval! If you need to delay an evaluation, write a function, which performs the evaluation, when you call it. Substituting Bash Variable in a export Command. In case of removing the You are not running the script under bash. Bash Script - Wrapping Variables in Quotes. Suppose, if I pass the value of login_token directly in the curl command, then the authentication is successful. This has the "${var@Q}" expansion which quotes the variable such that it can be parsed back by bash. How to pass arguments in double quotes inside bash script. After reading other posts I tried putting the command in an array, but I As a general rule, I will always quote variable expansions even when I know the value won't contain any IFS characters because I want to be in the habit. I have tried many commands to remove the double quotes from the string and none of them seem to work. How to get bash not to treat [ as a test character when using command substitution? 0. Assume that the ¹In ksh93 and pdksh and derivatives, brace expansion is also performed unless globbing is disabled (in the case of ksh93 versions up to ksh93u+, even when the braceexpand option is disabled). The special parameters * and @ have special meaning when in double quotes (see Shell Parameter Triple quotes have no special meaning in bash: two of the quotes cancel each other out, leaving only the third; making the behavior 100% identical to just using only one quote. You're seeing bash trying to show you that it got "*" after quote removal, so it will have to pass the double quotes on to the command. Double Quotes: What Are the Differences? Use single (') and double quotes (") in bash shell scripts or when executing Variables are not expanded within single quotes. This makes sense, Variables are expanded in double quotes, but not single quotes! Your first "This makes sense" example is flawed. Do take care: leaving out the quotes can lead not just to errors but to security holes. If you quote the here-doc delimiter (EOF in the code below), variable references are also not expanded. Share. 11 Difference between single and double quotes in Bash. Using Arithmetic Expansion. Next, we learned how double Your shell is not passing the quotes through to the script. Modified 5 years, 11 months ago. The one exception is I don't quote the value when doing a variable assignment (unless In Bash, you could use the following one-liner: [[ "${var}" == \"*\" || "${var}" == \'*\' ]] && var="${var:1:-1}" This will remove surrounding quotes (both single and double) from the string stored in var while keeping quote characters inside the string intact. Share In bash script, I have a variable, say $date, that obtained string value from some other function, say the value of $date is 04 Feb 2020. Learning the language well enough to understand those edge cases might be useful, but expecting others I have the following bash script: set -ex X="bash -c" Y="ls -al" I want to execute (notice the double quotes): bash -c "ls -al" The following does not work: Escaping double quotes for variables in bash and qmake. I would like to escape one of the variables (e. sh Note: variables are by default expanded inside variable definitions so take care with any $ characters inside the variable value (they must be written as $$ to be literal). My bash execution keeps escaping my internal argument, no matter what. Variable and function references in recipes have identical syntax and semantics to references elsewhere in the makefile. You would use single quotes if you want to use "$1" literally, without Bash interpreting it as a variable. The embedded double quotes and forward slash (in the variable) are causing your problems; the forward slash can be addressed with a different delimiter (as @Rachid has pointed out). Addendum: Supporting Non-Bash Remote Shells. Case 3: Remove Outermost Quotes from String. but you may also want to just use variables like: myjob: variables: EXPECT_SERVER_OUTPUT: '{"message": "Hello World"}' script: - dothething. steps: - script: | echo ##vso[task. ² In ksh93 and yash, arithmetic expansions can also include things like 1,2, 1e+66, inf, nan. Then, another problem that I do not understand yet, is that scp doesn't want to copy files with if it is enclosed in double quotes "my-file" within the variable. In this tutorial, you A single-quote cannot occur within single-quotes. The special parameters * and @ have special meaning when in double quotes (see Shell Parameter In my Bash environment I use variables containing spaces, and I use these variables within command substitution. sh: 4: [: Hi" a/b/c:: unexpected operator As shown here, your script works under bash but not dash. Once single quote is found replace it with double quote. Variable - Yes; Wildcards - No; Command substitution - yes; The single quote ( 'quote' ) protects everything enclosed between two single quote marks. So, always try to define I'd like to escape single and double quotes while running a command under a > echo $'\'single quote phrase\' "double quote phrase"' 'single quote phrase' "double quote phrase" From man bash. EDIT: Question was marked as a duplicate, please observe that value is sent in a specific way with double quotes like "--parameter value" "--parameter2 value2" this question has not been asked and does not have an answer. The immediate two problems are that you cannot nest double quotes, and /"*"/ is almost certainly not the correct regex. echo ""a and t3=""a"" are pointless uses of Using sed to substitute string in in double quote with a bash variable. Commented Nov 24, 2023 at 19:10. Single quote within double quotes and the Bash reference manual. Shell script double quotes. Context of Double Quotes in Bash. How to quote a variable in bash script. I am aware that for variables to be expanded, you have to enclose the whole regex in double quotes (sed substitution with bash variables). An array variable whose members are the line numbers in source files where each corresponding member of FUNCNAME was invoked. Here, we are telling awk to replace s which is equal to single quotes. I found out and that I must study: it's not necessary to add the quotes as variable value, bash does everything right and magically for me. The following to lines are identical to bash: 'foo bar' foo' 'bar There is no need to quote the alphabetic characters - but it enhances the readability. Single quotes (' ') operate similarly to double quotes, but do not permit referencing variables, since the special meaning of $ is turned off. sed | replace value with environment variable containing double quotes. You can nest double quotes within double quotes by escaping them though. Bash export and use variable with quotes and space in script. Where the single-quoting ends, your env. There is a solution: put OPTIONS in an array, instead of a simple variable (and use double-quotes around all variable references, to keep spaces from getting treated as word separators). Poor whiskers takes a tumble. In a nutshell, double quotes are necessary wherever a list of words or a pattern is expected. Replace '{"secret":"$1 Put your newline in a variable, use the variable wherever you need a newline and change the quotes around your larger string to double quotes. Use the double quotes when you want only variables and command substitution. This ignorance is similar to the other common mistake of not using double quotes to prevent inadvertent word splitting or globbing. Problem. My problem is that every variable get "double quots". 756. Quotes within Bash Shell variable do not work, why? 4. Facing syntactical problems while writing Inline bash Command. Using double-quotes within double-quotes in bash. Wrap it with Single Quotes or Double Quotes. I need to wrap a substitute variable in double quotes in shell. Escape double quote inside a single quote. py some parametr in "double" quotes and with {brackets} So, if you see '"*"' in the debug output, you're not seeing bash adding single quotes. echo variable result in quotes BASH. sh $ dash script. If it turns out there are other things you need to escape besides double-quotes (like, say, backslashes themselves), you can add them to the sed [] expression (e. Enclosing characters in double quotes (‘"’) preserves the literal value of all characters within the quotes, with the exception of ‘$’, ‘`’, ‘\’, and, when history expansion is enabled, ‘!’. If you do call this from a script and $1 is indeed defined, then replace your single quotes with double quotes and your double quotes with either single quotes or escaped double quotes. 1. Commented Jul 4, Escaping javascript variable double quotes. When I do ls -lt on this variable The double-quotes around the -e argument are for support of filenames with spaces. This works because quoted strings next to each other are considered a single string and you can switch Double quotes in bash. flv Obviously, ${date} won't expand in single quote, please also note that there is a double quote beyond the single quote, which makes it even more complicated. Hot Double quotes in Bash enclose string values. Exporting quoted variables from result of command. Thus, FUNCNAME[0] is trace, whereas FUNCNAME[1] is foo; whereas BASH_LINENO[0] is the line A double quote may be quoted within double quotes by preceding it with a backslash. sh asd \"asd\" \'asd\' Double quotes (") in bash allow partial interpretation of special characters. bash:variable with double quotes. ${x#"*"} The literal <asterisk> is quoted and not special. Follow answered Feb 13, 2017 at 16:02. Passing python variable to embedded shell script? 1. 936. In regular expressions, * simply means to repeat the previous expression zero or more times, as many as possible. Learn Bash - Double quotes for variable and command substitution. Note that this approach will fail horribly if the string contains any newlines (which is legal in filenames). Because the shell won't let you escape quotes, you need to turn it into multiple abutting quoted strings, switching between single and double quotes as needed to protect what's inside. See here: Bash: add value to array without specifying a key. /script. Modified 2 years, 9 months ago. Modified 7 years ago. They are only used to disable interpretation of various special characters, like whitespace, Note the use of ${BASH_LINENO[0]} and ${FUNCNAME[1]}; this is because BASH_LINENO is defined as follows:. Wiktor Stribiżew Adding double quotes to beginning, end and around comma's in bash variable. Escape single quotes in shell script. 1 of the POSIX shell syntax specification:. [1] Double-quotes are optional, ONLY IF the literal part of your RHS (the value to assign) contains neither whitespace nor other shell metacharacters. Demo: In shell, "quoting is used to remove the special meaning of certain characters or words to the shell" (bash manual). Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers; Advertising & Talent Reach devs & technologists worldwide about your product, service or employer brand; OverflowAI GenAI features for Teams; OverflowAPI Train & fine-tune LLMs; Labs The future of collective knowledge sharing; About the company Key point is that without double quotes, the contents of variables are understood as separate units rather than one whole item. – Jonathan Dodds. I want to add a variable ${date} in the following bash script: ffmpeg -i in. awk -v s="'" '{gsub(s,"\"")}1' file OR In this case, the primary problem is that you're trying to define OPTIONS as containing multiple words, and bash variables don't handle this very well. So what I need to do is call the variable such that it's value is swapped into the function and wrapped with double-quotes("), but avoid the name of the variable being read as a literal string. Use single quotes for static strings and double quotes for strings containing variables. so I really need a way to escape the quote after the variable has been created – Sulli Commented May 8, 2017 at 10:34 I write a bash script and get some user input with read. Find and kill a Nothing inside single quotes will be expanded by bash, including any double-quotes, and variable names. You have to leave the single quoting or your variable won't be evaluated. Arithmetic expansion refers to the process of performing the arithmetic operation in shell scripting. If you had a target system with a shell which didn't support extensions to POSIX such as $'', this guarantee would no longer be available, and How to execute bash variable with double quotes and get the output in realtime. The backslash preceding the ! is not removed. Getting started with Bash; Variable There's a trick you can use anytime you need to have the shell accept as a single argument something that has both single quotes and double quotes. It is not strictly meaningless because it can count as an argument, for instance: echo a b is different from echo a "" b. This simplifies this answer to: echo "Failed: foo: " "${mycmd[@]@Q}" This will correctly handle single quotes in an argument, which my earlier version did You can achieve this by using double quotes around the entire JSON string and escaping the inner double quotes, like this: curl -i -H "Content-Type: application/json" -X POST -d " Expand bash variable within quotes. Please note that I do not control the definition of the STRING variable, I receive it through an unmatched double quote; by default quotes are special to xargs unless you How to escape double quotes in bash command. 3 Double Quotes. how does 'Brace expansion' work in Bash? 1. Nested double quotes for wrapping variables. I have a variable in my bash script whose value is something like this: ~/a/b/c Note that it is unexpanded tilde. Repeat char n times in zsh prompt. The problem is the unexpected operator. Replace a string with single quotes using sed. ["\] would escape double-quotes and backslashes). And a single quote to start the next single quoted string. NOTE: The following applies to bash, ksh, and zsh, but NOT to (mostly) strictly POSIX compliant shells such as dash; thus, when you target /bin/sh, you MUST double-quote the RHS of export. Viewed 203 times 1 This question already has answers here: The Problem: Single Quotes Aren't Syntactic Within Double Quotes. Filename expansion is not performed between quotes. Viewed 1k times 1 . Any help would be greatly appreciated - I am pretty new to AWK. Take a look at the Advanced Bash Scripting Guide, specifically section 5. You should be wondering where those double quotes came from, and I'd guess that's from your input file. For example, part of bash; shell; variables; double-quotes; Share. I'm extremely confused with this, I miss Python! Mind -- why do you think you need to use double quotes here? Shell quoting is character-by-character -- even if you need double quotes for part of your string for a reason that isn't shown here, that doesn't mean you need to use them for the whole thing. Note that without double quotes, two things happen. ttf:text='Today is ${date}':fontsize=6" out. The best you can do with single quotes is to use '\'' wherever you need an embedded single quote. They prevent field splitting on result of $( dirname "${BASH_SOURCE[0]}" ), and also the expansion of ${BASH_SOURCE[0]} (In contrast with the outer most double quotes, will are not necessary in RHS of variable assignment to prevent split+glob). Within single quotes every character will be taken literally. Ask Question Asked 5 years, 11 months ago. $_), in such way that " and \ are escaped with a backslash. how to run shell script command with double quotes in the argument? 0. to do globbing and file name expansion). You should also always quote any variable that contains a filename. In the case bash's export though, you need the posix option to be enabled (like when it's invoked as sh) for that output to be in sh . How do I iterate over a range of numbers defined by variables in Bash? Load 7 more related questions Show fewer related questions Sorted by: Reset to default Browse other questions Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers; Advertising & Talent Reach devs & technologists worldwide about your product, service or employer brand; OverflowAI GenAI features for Teams; OverflowAPI Train & fine-tune LLMs; Labs The future of collective knowledge sharing; About the company The backtick at the end of your find command indicates that you are redirecting the command output to a variable. Even if you weren't piping the results to tr, it's possible that your variable wouldn't show newlines unless quoted. 638. 3 Double-Quotes. The standard command to output all the environment variables mapped to shell variables as shell code that can be interpreted to set the same environment variables is export -p. When using Bash correctly on a Linux environment, this can happen when debugging is on (set -x). Hot Network Questions the problem is that my variable gets its content from a file, I am not defining it myself. 0. Single quotes ' and double quotes " are treated differently in Bash, and you will need to know the difference if you are writing a Bash script. Ask Question Asked 7 years ago. Follow Learn Bash - Double quotes for variable and command substitution. 9. I am on CentOS 6. Difference between single and double quotes in Bash. 1464. Double-quoted characters will mostly taken literally, with the main exeption (among some others): variables will be replaced with their contents. Learn how to do quoting and variable parsing/validation properly from the outset, and avoid many of these issues! Let’s get started In this tutorial series you will learn: How to quote your Bash variables properly; The caveats Double Quotes in Bash's variable substitution. What is the correct way to quote my variables? Bash: Escaping double quotes in $() command substitution. Personally, I find the style of over-quoting to be a bit excessive. Shell script: single quote escaping. Ask Question Asked 4 years, 7 months ago. This used awk's inbuilt gsub function to search and replace the text. 1 which covers quoting variables. 3. So, i need to make grep of line. " Assigning default values to shell variables with a single command in bash. I would read the last line as suggesting that quote removal for double quotes applies to the word. You will have to escape them and it Thanks to dimo414's answer to a similar question, this shows how his great solution works, and shows that you can have quotes and variables in the text easily How to store multiple commands in a bash variable (similar to cat The reason to use double quotes instead of single quotes is to allow variable interpolation. Guessing a bit as to what you might hope your code should do, I imagine you are looking My solution was, to check first if file or directory meets some criteria, add its name to a variable and when my loop finishes, it will copy everything via scp. ($( ) creates a new quoting context, so you don't need to escape double quotes inside it at all in the first place; it's only backticks that have a problem there). In order to get the variables bash needs a double-quote string. If enabled, history expansion will be performed unless an ! appearing in double quotes is escaped using a backslash. I can change the single quote to double quote and use backslash to escape: Unlike scalar variables, which are just ordinary strings of ordinary characters no matter how many quotes they might contain, arrays are lists of strings, each one distinguished from each other one. #!/usr/bin/env bash #reads the JSON value of the file-path key. Ask Question Asked 7 years, 4 months ago. Ask Question Asked 8 years, 1 month ago. Double quotes preserve all characters inside them, with some exceptions: $ <dollar-sign>: used in variable interpolation and command substitution ` <grave-accent>: used in Using Double Quotes > echo "Hello, LinuxSimply!" Output > Hello, LinuxSimply! Alongside, when you define any variable by enclosing it with single quotes, Bash doesn’t consider it as a variable. In this sense, bash is just like almost every other programming language. variable will be evaluated instead of being treated literally. In your case, only special characters like " and < must be quoted. The characters $ and ` retain their special meaning within double quotes. Tags; Topics; Examples; eBooks; Download Bash (PDF) Bash. Then, we saw how quotes disable word splitting for the quoted expression. Since you need the HTTP PUT body itself to have both single and double quotes – you need to send the string '"SHUTTING_DOWN"' with both kinds of quotes over the wire – getting rid of I would like to do this without spawning a new bash process or using eval because I do not want to take the risk of having random commands executed. Also, this won't do anything if there's only a single leading quote or only a single trailing quote or if there are mixed quote To solve this issue in Bash script, you need to remove double quotes or single quotes. how can I find and replace the string with quote? 1. So removing backslashes should fix the issue. 6. Improve this answer. bashrc file. Why am I not able to detect if the file exist with this linux shell script? Related. bash variable string with quotes and double quotes. That said, on a glance, what you're doing there looks good to me -- which is to say that it should be substituting in the variables in question; whether the result is a valid document Quotation on a Linux system can be a source of confusion at first. As per gnu make official doc:. Strange issue resolving bash environmental variable in nested double quotes. Bash: It is not putting quotes around each field like the importer requires. In the second case, $@ is expanded out to rsync -avz -e ssh -c blowfish source user@remote:dest/, missing the single quotes. -type f -mtime -100 -daystart -printf '"%f"\n') Double quotes in bash variable assignment and command substitution. The end result I'm after is for my script to call: lwp-request -U -e -H "Range: bytes=20-30" My script file looks like: I know the question is about bash but for POSIX compatible system where the string must contain both single and double quotes you have to mix between both without spaces in between. Consider single quotes ("full quoting") to be a stricter method of quoting than double quotes ("partial quoting"). \nShe's fine, though, don't worry. Replace value containing quotes with sed command and regex. Find it here: $ echo "Ehm, \"hi\", he \\ said" | awk '1' Ehm, "hi", Always double-quote your variables (unless you really know exactly when you don't need to do so) How to execute a command that has many nested single and double quotes with a quoted variable in bash. I spent a couple hours trying to figure out how to add this to the existing script, without much luck. Example: When you pass a string with Bash, you have to take into consideration what echo itself is performing with the double quotes. I am trying to configure some software packages with a script thereby I got the following problem. This works because quoted strings next to each other are considered a single string and you can switch A double quote may be quoted within double quotes by preceding it with a backslash. From Bash Reference Manual on Quoting: 3. setvariable variable=BASE_URL The additional " of the echo commands will be given out and be considered part of the variable. In the original example you have a layer of quotes from YAML, plus a layer of quotes from the sh -c wrapper. Ask Question Asked 10 years, 7 months ago. Modified 4 years, 7 months ago. not a good solution if the sql query contains double-quotes. That's a single quote to end the single quoted string. 27. Like this: stackoverflow =&gt; 'stackoverflow' And then append this string to another variable separated by a 'comma'. to let a variable expand) or need to use no quotes (e. Javascript Quote inside of Assume . I have also tried to escape the double quotes within the variables, but again, the behaviour is the same! I have even tried to remove the quotes, For bash, every quote inside the quoted string must be escaped. bash_profile: echo 'alias N="cd $(pwd If the value itself contains double quotes, those double quotes will be escaped and hence should work fine. All spaces are replaced with ',' using sed "s/ /','/g", and the initial and trailing single quotes are added inside a double quoted string. /program ${args} Hello there # This is 1 argument I have two bash variables, one called GREP_ENTRY, Using double quotes and variables in sed command [duplicate] Ask Question Asked 4 years, 7 months ago. bash: quote var with quotes. Using sed to substitute string in in double quote with a bash variable. What happens to arguments passed to bash/ash functions? 3. 886 1 1 gold Print a variable in single quote on bash | Weird Variables. Modified 8 years, 1 month ago. Update, because I think you lack some fundamental shell programming knowledge. "Today is ${date}. What happens without quotes. command "string" This string is stored in variable var1. The backslash preceding the ‘!’ is not removed. BASH - replace with variable contain double quotes inside. Modified 7 years, 4 months ago. " from the first link, but for my usage, the data that is given to a function (in this case, at) is code. anaotha anaotha. /program "Hello there" Hello there How can I properly pass arguments with quotes in from a variable? I am trying to do this; $ args='"Hello there"' $ echo ${args} "Hello there" $ . Outside of double quotes, $var takes the value of var, splits it into whitespace-delimited parts, and interprets each part as a Wrap it with Single Quotes or Double Quotes. sh script. Single quote escaping in Bash within a single quoted string. Hot Network Questions Sci-fi / futurism supplement from a UK newspaper in 1999/2000 Using sed to substitute string in in double quote with a bash variable. py 'some parametr in "double" quotes and with {brackets}' temp. Viewed 724 times 1 . A double quote may be quoted within double quotes by preceding it with a backslash. Note that have both quotes and double quotes. It should be quite safe to use. First, we understood how Bash performs word splitting. i am writing personal parser for json on bash. Bash would accept that non-standard syntax. The double quote ( "quote" ) protects everything enclosed between two double quote marks except $, ', " and \. Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers; Advertising & Talent Reach devs & technologists worldwide about your product, service or employer brand; OverflowAI GenAI features for Teams; OverflowAPI Train & fine-tune LLMs; Labs The future of collective knowledge sharing; About the company bash variable with double-quotes. A system running Linux. Example: Edit: A bunch of people have pointed out that the variables get expanded in double quotes before bash -c gets run. If enabled, history expansion will be performed unless an ‘!’ appearing in double quotes is escaped using a backslash. The value of login_token variable should be passed without quotes as it is. One caveat: printf %q is guaranteed to quote things in such a way that bash (or ksh, if you're using printf %q in ksh locally) will evaluate them to exactly match the input. Hot Network Questions Both of NASA's ARED devices have a sign with the acronym "PLEASE;" what does it stand for? An array is a multi-element variable, so is this to say that the former also is an array for all purposes? If the former is an array, is the only difference in operation as between (a) the double quotes and (b) the parentheses, the operation of quoting rules on the array's elements? Many thanks for any insights. $' is a special syntax (fully explained here) which enables ANSI-C string processing. I have to be more precise, I have some white space and the real command is mycommand -f "a a","b". I tried below methods I'm trying to write a bash script, and I'm running into a quoting problem. variable expansion in curly braces. If you want to pass quotes, escape them with a backslash: # . " Bonus: Doing this way you won't have to escape your single quotes. Escaping double quotes inside command substitution. Learning about the double quotes in Bash. Variable expansion in Bash. The thing is that the string I am searching for is also enclosed in double quotes, that is why I enclosed the whole regex in single quotes. They also have the same quoting rules: if you want a dollar sign to appear in your recipe, you must double it (‘$$’). 000 line like the string. I have a I'm not sure what I did differently today vs yesterday but just enclosing the variable in double quotes worked. Double quoting is not always needed , but it's easier to remember to always double quote than to memorize the contexts in which you don't need to. The double quotes can be addressed a few ways, one idea: @Bianca Just quote both variable expansions with double quotes and it will be solved. I like the quote "Variables hold data, functions hold code. Other shells may reject. 1. Hot Network Questions How to I am trying to add quotes to a string. 4 has been released. Double double quotes is an empty double quote. Double quote (” “) is a flexible quoting type that serves multiple Using $ as a prefix tells BASH to try to find a variable with that name. Import variable into jq. 5. Double Quotes in Bash's variable substitution. sed replace double quoted text, single quoted working. 2. Further, in your original command, you could have used single quotes to do away with double-quotes escaping. 1 is to print the line. Bash pass variable as argument with quotes. Follow edited Nov 30, 2021 at 12:20. It's possible to store it on a variable in BASH? An important cosideration: I can't add \" or \', because is a text file with 150. How can I prevent this? echo "Whats your name?" read yourname cat << EOF >> /path/to/file Your Name is "${yourname}" EOF The content of the file is: Prerequisites. Key Takeaways. "${x#*}" The <asterisk> is a pattern character. 4. Bash variable expansion syntax with braces. – mivk. From the above image, you can see that I have removed single quotes from the string ‘Hello, LinuxSimply!‘ by using the parameter expansion. There are even more in zsh, including # which is a glob operator with extendedglob, but I'd suggest getting rid of as many layers of quotes as you can. . The reason you double quote variables is because the contents of the variable may In this article, we learned about the use of double quotes in Bash. Running shell command and capturing the output. Finding edge cases in the language to avoid double quoting is folly. The good news is you can end your single-quoted section and immediately start a double-quoted section to introduce the variable, and it will all be concatenated into a single argument for the application (curl). Related. Using ($’’) Syntax to Escape Double Quotes in Bash. Use single quotes, if you string contains double quotes and vice-versa. The double-quotes, braces, dollar-sign, etc have no syntactic significance to the shell, because they're in single I suspect it is due to double quotes being placed around my variable somehow. tcsh: Handle spaces in arguments when passing on to another command. I am basically trying to use the filePath variable in my git command with no double quotes around it. Hot Network Questions How to calculate multiple SDF's from points sampled on some surface as a face attribute in geometry nodes Edit: Almost 5 years later and since I answered this question, bash 4. The output shows successful string interpolation using command substitution. Temp python temp. If, like me, you never use bash expansion in your shell, disabling it will allow you to use exclamation points in any double-quote string - not only during your commits but for all bash commands. You need to use double-quote string for the JSON and just escape double-quote characters inside JSON string. How to get a Always double quote variable expansions, unless you explicitly want the shell to perform word-splitting and filename generation (globbing) on the strings. Thanks a lot. export will take care of quoting the value as appropriate. Ask Question Asked 2 years, 9 months ago. @OphirHarpaz, if you want to know if your changes are correct, use bash -x yourscript to see exactly what is being passed to curl (though that's shell-escaped, as opposed to byte-for-byte). Security implications of forgetting to quote a variable in bash/POSIX shells; Share. Exploring practical examples of double quotes in Bash. How to Replace a column in one file with shell script variable and keep the Double quotes that are After reading a lot of info about double-quotes, I presume I can/must exclude wildcards from double-quote when I need (for example) to loop over files but I'd like to be sure. Follow answered Jun 8, 2020 at 15:10. if my commit message has double quotes, independent of combining all 3 Bash pass variable as argument with quotes. The basic it will be logged to the syslog without the single quote around the user/host, just: mysqld: 150114 3:40:50 [Warning] Access denied for user [email protected] (using password: YES) that make fail2ban failed to recognized as it does not match the filter regex. For example, foo=$(find . pattern='path with wildcard*' IFS= # disable splitting shopt -s nullglob # make globs that don't match any file expand to nothing # instead of the unexpanded pattern. As you can verify, each of the above lines is a single word to the shell. Wenfang Du. So you are matching "", """, """" etc. Enclosing characters in double-quotes ("") shall preserve the literal value of all characters within the double-quotes, with the exception of the characters backquote, <dollar Quoting when the variable is defined (or embedding quotes or escapes in the variable's value) doesn't prevent it from being word-split when it's used; you really need to double-quote when using the variable to prevent weird parsing. flv -vf drawtext="fontfile=Sans. Each variable assignment shall be expanded for tilde expansion, parameter expansion, command substitution, arithmetic expansion, and quote removal prior to assigning the value. In this case, the single tick isn't "take value verbatim until the next single tick". String-splitting and globbing (the steps which double quotes suppress) are not in this list, and the others aren't relevant Escaping a double quote can absolutely be necessary in sed: for instance, if you are using double quotes in the entire sed expression (as you need to do when you want to use a shell variable). How to remove double-quotes in jq output for parsing json files in bash? 807. Bash Separate values with commas then surround them with quotes in variable. For example string="single quote: ' double quote: "'"'" end of string". Quotes (single or double quotes, depending on the situation) don't isolate words. If the parameters are given double quoted like "--parameter value" "--parameter2 value2", how can I pass them so that an end Which of course is because of the double quotes in the jq command. Either you can do like William suggests, or you can rewrite the line into double quotes, which will expand the variable as you want. How to Following will convert all the single quotes to double quotes. Bash will not insert variables into a single-quote string. Are those double quotes necessary? Based on the following test, I'd say no, and that no quote at all is needed in the above assignment. The drawbacks are it's BASH only and quite uncommon, so many people will wonder what it means. fkvpja lvig hlnz eoilnsf bfqlh kqrip mjsloj dxpodrax eoenkyi bvagm